Question

1. given:

initial horizontal velocity (vₓ₀): 1.67 m/s
total time (t): 13.2 s
angle (θ): 0°
wanted: distance (x) in m?
distance? m

Explanation:

Step1: Identify the formula for horizontal distance

For projectile motion with an initial horizontal velocity \( v_{x0} \) and time \( t \), the horizontal distance \( x \) is given by the formula \( x = v_{x0} \times t \) (since there is no horizontal acceleration when \( \theta = 0^\circ \), the horizontal velocity remains constant).

Step2: Substitute the given values

We know \( v_{x0} = 1.67 \, \text{m/s} \) and \( t = 13.2 \, \text{s} \). Substituting these values into the formula:
\( x = 1.67 \, \text{m/s} \times 13.2 \, \text{s} \)

Step3: Calculate the product

\( 1.67\times13.2 = 22.044 \)

Answer:

\( 22.044 \)