QUESTION IMAGE
Question
- given: \\(\overline{ab} \cong \overline{ed}\\), \\(\overline{ab} \parallel \overline{de}\\), \\(c\\) is the midpoint of \\(\overline{ae}\\)\
prove: \\(\triangle abc \cong \triangle edc\\)\
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- given: \\(\overline{yx} \cong \overline{zx}\\), \\(\overline{wx}\\) bisects \\(\angle yxz\\)\
prove: \\(\triangle wyx \cong \triangle wzx\\)\
\
- use the coordinates below to determine if \\(\triangle abc\\) and \\(\triangle def\\) are congruent.\
\\(\triangle abc\\): \\(a(2, -8)\\), \\(b(-5, -2)\\), \\(c(-7, 3)\\); \\(\triangle def\\): \\(d(-9, 7)\\), \\(e(-11, 12)\\), \\(f(-2, 1)\\)\
\\(ab = \\) \\(de = \\)\
\\(bc = \\) \\(ef = \\)\
\\(ac = \\) \\(df = \\)\
are the triangles congruent? if yes, explain your reasoning and write a congruency statement.
Problem 9: Prove $\triangle ABC \cong \triangle EDC$
Step 1: List Given Information
- $\overline{AB} \cong \overline{ED}$ (Given)
- $\overline{AB} \parallel \overline{DE}$ (Given)
- $C$ is the midpoint of $\overline{AE}$ (Given)
Step 2: Identify Vertical Angles
$\angle ACB \cong \angle ECD$ (Vertical angles are congruent)
Step 3: Identify Alternate Interior Angles
Since $\overline{AB} \parallel \overline{DE}$, $\angle A \cong \angle E$ (Alternate interior angles are congruent)
Step 4: Midpoint Implies Congruent Segments
$C$ is the midpoint of $\overline{AE}$, so $\overline{AC} \cong \overline{EC}$ (Definition of midpoint)
Step 5: Apply ASA Congruence
In $\triangle ABC$ and $\triangle EDC$:
- $\angle A \cong \angle E$ (Step 3)
- $\overline{AC} \cong \overline{EC}$ (Step 4)
- $\angle ACB \cong \angle ECD$ (Step 2)
Thus, $\triangle ABC \cong \triangle EDC$ (ASA Congruence Postulate)
Problem 10: Prove $\triangle WYX \cong \triangle WZX$
Step 1: List Given Information
- $\overline{YX} \cong \overline{ZX}$ (Given)
- $\overline{WX}$ bisects $\angle YXZ$ (Given)
Step 2: Angle Bisector Implies Congruent Angles
$\overline{WX}$ bisects $\angle YXZ$, so $\angle WXY \cong \angle WXZ$ (Definition of angle bisector)
Step 3: Identify Common Side
$\overline{WX} \cong \overline{WX}$ (Reflexive Property of Congruence)
Step 4: Apply SAS Congruence
In $\triangle WYX$ and $\triangle WZX$:
- $\overline{YX} \cong \overline{ZX}$ (Given)
- $\angle WXY \cong \angle WXZ$ (Step 2)
- $\overline{WX} \cong \overline{WX}$ (Step 3)
Thus, $\triangle WYX \cong \triangle WZX$ (SAS Congruence Postulate)
Problem 11: Determine if $\triangle ABC$ and $\triangle DEF$ are Congruent
We use the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Calculate $AB$ (for $\triangle ABC$):
$A(2, -8)$, $B(-5, -2)$
$$AB = \sqrt{(-5 - 2)^2 + (-2 - (-8))^2} = \sqrt{(-7)^2 + (6)^2} = \sqrt{49 + 36} = \sqrt{85}$$
Calculate $DE$ (for $\triangle DEF$):
$D(-9, 7)$, $E(-11, 12)$
$$DE = \sqrt{(-11 - (-9))^2 + (12 - 7)^2} = \sqrt{(-2)^2 + (5)^2} = \sqrt{4 + 25} = \sqrt{29}$$
Calculate $BC$ (for $\triangle ABC$):
$B(-5, -2)$, $C(-7, 3)$
$$BC = \sqrt{(-7 - (-5))^2 + (3 - (-2))^2} = \sqrt{(-2)^2 + (5)^2} = \sqrt{4 + 25} = \sqrt{29}$$
Calculate $EF$ (for $\triangle DEF$):
$E(-11, 12)$, $F(-2, 1)$
$$EF = \sqrt{(-2 - (-11))^2 + (1 - 12)^2} = \sqrt{(9)^2 + (-11)^2} = \sqrt{81 + 121} = \sqrt{202}$$
Calculate $AC$ (for $\triangle ABC$):
$A(2, -8)$, $C(-7, 3)$
$$AC = \sqrt{(-7 - 2)^2 + (3 - (-8))^2} = \sqrt{(-9)^2 + (11)^2} = \sqrt{81 + 121} = \sqrt{202}$$
Calculate $DF$ (for $\triangle DEF$):
$D(-9, 7)$, $F(-2, 1)$
$$DF = \sqrt{(-2 - (-9))^2 + (1 - 7)^2} = \sqrt{(7)^2 + (-6)^2} = \sqrt{49 + 36} = \sqrt{85}$$
Compare Side Lengths:
- $AB = \sqrt{85}$, $DF = \sqrt{85}$
- $BC = \sqrt{29}$, $DE = \sqrt{29}$
- $AC = \sqrt{202}$, $EF = \sqrt{202}$
By SSS (Side-Side-Side) Congruence, $\triangle ABC \cong \triangle DFE$ (since $AB \cong DF$, $BC \cong DE$, $AC \cong EF$).
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s:
Problem 9 (Table):
| Statements | Reasons |
|---|---|
| 2. $\overline{AB} \parallel \overline{DE}$ | Given |
| 3. $C$ is the midpoint of $\overline{AE}$ | Given |
| 4. $\angle A \cong \angle E$ | Alternate Interior Angles (from $AB \parallel DE$) |
| 5. $\overline{AC} \cong \overline{EC}$ | Definition of Midpoint |
| 6. $\angle ACB \cong \angle ECD$ | Vertical Angles Congruent |
| 7. $\triangle ABC \cong \triangle EDC$ | ASA Congruence |
Problem 10 (Table):
| Statements | Reasons |
|---|---|
| 2. $\overline{WX}$ bisects $\angle YXZ$ | Given |
| 3. $\angle WXY \cong \angle WXZ$ | Definition of Angle Bisector |
| 4. $\overline{WX} \cong \overline{WX}$ | Reflexive Property |
| 5. $\triangle WYX \cong \triangle WZX$ | SAS Congruence |
Problem 11 (Table):
| $AB = \boldsymbol{\sqrt{85}}$ | $DE = \boldsymbol{\sqrt{29}}$ |
| $BC = \boldsymbol{\sqrt{29}}$ | $EF = \boldsymbol{\sqrt{202}}$ |
| $AC = \boldsymbol{\sqrt{202}}$ | $DF = \boldsymbol{\sqrt{85}}$ |
Congruence: Yes, $\triangle ABC \cong \triangle DFE$ (SSS Congruence, since all corresponding sides are congruent).