Question

go step by step to reduce the radical. $sqrt{32}$ $sqrt{16} cdot sqrt{2}$ $squaresqrt{square}$ try

Explanation:

Step1: Simplify $\sqrt{16}$

$\sqrt{16} = 4$

Step2: Substitute back to the expression

$4 \cdot \sqrt{2}$

Answer:

$4\sqrt{2}$