Question

the goal is to construct a grouped frequency distribution table (gfdt) for this data set. the gfdt should have 10 classes with a
ice\ class width. each class should contain its lower class limit, and the lower class limits should all be multiples of the class width. it has been determined that the ideal class width would be 0.25. this problem is to determine what the first lower class limit should be. what is the minimum of this data set? min = what is the minimum divided by the class width? minimum ÷ class width = this number rounds down to what integer? using this value, if the goal is to have a lower class limits that are multiples of the class width, what should be the first lower class limit? 1st lower class limit = question help: video device will power down soon 5% battery left (about 21 minutes) connect your device

Explanation:

Step1: Find minimum value

Since the data - set is not given, we assume we need to follow the general procedure. Let's say the minimum value of the data - set is $x_{min}$. But for the sake of the steps, we'll work symbolically.

Step2: Divide minimum by class width

Let the class width $w = 0.25$. The result of the division is $\frac{x_{min}}{w}$.

Step3: Round down the result

Let $n=\lfloor\frac{x_{min}}{w}
floor$, where $\lfloor\
floor$ is the floor - function that rounds down to the nearest integer.

Step4: Calculate first lower class limit

The first lower class limit $L = n\times w$.

However, since the actual data - set is not provided, we cannot give numerical answers. If we assume the minimum value of the data - set is $x_{min}$, then:

Answer:

min = (Value of minimum of the data - set, not given)
minimum $\div$ class width=$\frac{x_{min}}{0.25}$
This number rounds down to $\lfloor\frac{x_{min}}{0.25}
floor$
1st lower class limit = $0.25\times\lfloor\frac{x_{min}}{0.25}
floor$