Question

the golden gate bridge in san francisco, california, was under construction from 1933-1937. suppose a construction worker dropped a tool from a point on the bridge that is 220 feet above the water.

an equation that gives the height (in feet) of the tool above the water as a function of time (in seconds) is
$h = -16t^2 + 220$

how high above the water is the tool after 3 seconds?

$circ$ 54 feet above the water
$circ$ 20 feet above the water
$circ$ 160 feet above the water
$circ$ 76 feet above the water

Explanation:

Step1: Substitute t = 3 into the equation

We have the height function \( h = -16t^2 + 220 \). Substitute \( t = 3 \) into this equation.
First, calculate \( t^2 \) when \( t = 3 \), so \( 3^2 = 9 \). Then multiply by -16: \( -16\times9=-144 \).

Step2: Calculate the height

Now add 220 to the result from Step 1. So \( h=-144 + 220 \).
\( h = 76 \).

Answer:

76 feet above the water (corresponding to the option: 76 feet above the water)