Question

a graduated cylinder initially contains 270 ml of water. an irregular shaped object is submerged in the cylinder and the water level rises to 620 ml. what is the volume of the submerged object? express your answer using the correct unit. 620 ml 890 l 350 l 350 ml

Explanation:

Step1: Identify initial and final volumes

Initial volume $V_1 = 270$ ml, final volume $V_2=620$ ml.

Step2: Calculate volume of object

The volume of the submerged object $V = V_2 - V_1$.
$V=620 - 270=350$ ml.

Answer:

350 ml