Question

graph the equation.

1. $y - 6 = 3(x - 4)$
2. $y + 2 = -(x - 1)$

Explanation:

Step1: Rewrite eq10 to slope-intercept form

Expand and isolate $y$:

$$\begin{align*} y - 6 &= 3(x - 4)\\ y - 6 &= 3x - 12\\ y &= 3x - 12 + 6\\ y &= 3x - 6 \end{align*}$$

Step2: Identify key points for eq10

• Y-intercept: When $x=0$, $y=3(0)-6=-6$, so point $(0, -6)$
• Another point: When $x=2$, $y=3(2)-6=0$, so point $(2, 0)$

Step3: Rewrite eq13 to slope-intercept form

Expand and isolate $y$:

$$\begin{align*} y + 2 &= -(x - 1)\\ y + 2 &= -x + 1\\ y &= -x + 1 - 2\\ y &= -x - 1 \end{align*}$$

Step4: Identify key points for eq13

• Y-intercept: When $x=0$, $y=-(0)-1=-1$, so point $(0, -1)$
• Another point: When $x=1$, $y=-(1)-1=-2$, so point $(1, -2)$

Answer:

For equation 10 ($y=3x-6$):

1. Plot points $(0, -6)$ and $(2, 0)$ on the first grid.
2. Draw a straight line through these two points.

For equation 13 ($y=-x-1$):

1. Plot points $(0, -1)$ and $(1, -2)$ on the second grid.
2. Draw a straight line through these two points.