Question

graph this function: $f(x) = x^2 - 4x - 5$
step 1: identify $a$ and $b$.
$a = 1$, $b = -4$
step 2: find the vertex using the formula $x = \frac{-b}{2a}$.
$x = \frac{4}{2(1)}$
$x = 2$
find the $y$-coordinate of the vertex:
$f(2) = 2^2 - 4(2) - 5$.
$f(2) = \square$

Explanation:

Step1: Calculate \(2^2\)

\(2^2 = 4\)

Step2: Calculate \(4(2)\)

\(4(2)=8\)

Step3: Substitute into the function

\(f(2)=4 - 8 - 5\)

Step4: Perform the arithmetic

\(4-8=-4\), then \(-4 - 5=-9\)

Answer:

\(-9\)