Question

1. graph the portion of y = 0.2x + 1 that lies in the first quadrant using the slope and y - intercept.

Explanation:

Step1: Identify y - intercept

The equation is in slope - intercept form $y = mx + b$, where $b$ is the y - intercept. For $y=0.2x + 1$, the y - intercept is 1. So the line crosses the y - axis at the point $(0,1)$.

Step2: Identify slope

The slope $m = 0.2=\frac{1}{5}$. This means for every 5 units we move to the right along the x - axis, we move 1 unit up along the y - axis.

Step3: Find x - intercept

Set $y = 0$:
$0=0.2x + 1$
$- 1=0.2x$
$x=-5$. But we are only interested in the first - quadrant part, so we start from the y - intercept $(0,1)$ and use the slope to plot more points in the first quadrant. Moving 5 units to the right from $(0,1)$ gives us the point $(5,2)$.

Step4: Graph

Plot the points $(0,1)$ and $(5,2)$ and draw a straight line between them (only the part that lies in the first quadrant).

Answer:

Graph the line starting at the point $(0,1)$ and using a slope of $\frac{1}{5}$ to plot additional points in the first quadrant.