Question

graph $h(x) = 7\sin x$.
use 3.14 for $\pi$.
use the sine tool to graph the function. graph the function by plotting two points. the first point must be on the midline and closest to the origin. the second point must be a maximum or minimum value on the graph closest to the first point.
graph with axes, grid, and sine tool interface, x-axis labels: -6.28, -4.71, -3.14, -1.57, 0, 1.57, 3.14, 4.71, 6.28; y-axis labels: -7, -6, ..., 7

Explanation:

Step1: Identify midline point

The midline of \(h(x)=7\sin x\) is \(y=0\). The point on midline closest to origin is (0, 0) since \(\sin 0=0\), so \(h(0)=7\times0=0\).

Step2: Find closest max point

The maximum value of \(\sin x\) is 1, occurring at \(x=\frac{\pi}{2}\approx1.57\). So \(h(1.57)=7\times1=7\), giving the point (1.57,7). This is the closest maximum to (0,0).

Answer:

First point: (0, 0); Second point: (1.57, 7)