QUESTION IMAGE
Question
graphing linear equations
vectored instruction
graph the
equation by filling
in the chart.
equation:
y = 3x+1
x y
0 1
1 4
2 7
3 ?
4
Step1: Substitute x = 3 into the equation
We have the equation \( y = 3x + 1 \). When \( x = 3 \), we substitute \( x \) with 3 in the equation.
\( y = 3\times3 + 1 \)
Step2: Calculate the value of y
First, calculate \( 3\times3 = 9 \), then add 1 to it.
\( y = 9 + 1 = 10 \)
Step3: Substitute x = 4 into the equation
When \( x = 4 \), substitute \( x \) with 4 in the equation \( y = 3x + 1 \).
\( y = 3\times4 + 1 \)
Step4: Calculate the value of y
First, calculate \( 3\times4 = 12 \), then add 1 to it.
\( y = 12 + 1 = 13 \)
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For \( x = 3 \), \( y = 10 \); for \( x = 4 \), \( y = 13 \)
So the completed table is:
| X | Y |
|---|---|
| 1 | 4 |
| 2 | 7 |
| 3 | 10 |
| 4 | 13 |