Question

the gross domestic product (gdp) of a certain country, which measures the overall size of the economy in billions of dollars, can be approximated by the function $f(y) = 612y + 8879$, where $y = 10$ corresponds to the year 2010. estimate the gdp (to the nearest billion dollars) in the given years: (a) 2004 (b) 2009 (c) 2012 (a) what value of $y$ corresponds to the year 2004? $y = 4$ (type a whole number.) the gdp in 2004 is about $11327$ billion. (b) what value of $y$ corresponds to the year 2009? $y = 9$ (type a whole number.) the gdp in 2009 is about $\square$ billion.

Explanation:

Step1: Identify the function and y-value

The function is \( f(y) = 612y + 8879 \) (assuming the original function has a plus sign, maybe a typo in the problem as \( 612y \cdot 8879 \) doesn't make sense for GDP growth, likely \( 612y + 8879 \)). For 2009, \( y = 9 \).

Step2: Substitute y into the function

Substitute \( y = 9 \) into \( f(y) = 612y + 8879 \).
\( f(9) = 612 \times 9 + 8879 \)
First, calculate \( 612 \times 9 = 5508 \).
Then, add 8879: \( 5508 + 8879 = 14387 \).

Answer:

14387