Question

the gross domestic product (gdp) of a certain country, which measures the overall size of the economy in billions of dollars, can be approximated by the function f(y) = 612y + 8879, where y = 10 corresponds to the year 2010. estimate the gdp (to the nearest billion dollars) in the given years. (a) 2004 (b) 2009 (c) 2012 (a) what value of y corresponds to the year 2004? y = 4 (type a whole number ) the gdp in 2004 is about $\square$ billion.

Explanation:

Step1: Identify the function and y-value

We have the function \( f(y) = 612y + 8879 \) and for 2004, \( y = 4 \).

Step2: Substitute y into the function

Substitute \( y = 4 \) into \( f(y) \):
\( f(4) = 612 \times 4 + 8879 \)

Step3: Calculate the multiplication

First, calculate \( 612 \times 4 = 2448 \)

Step4: Calculate the sum

Then, add 8879 to the result: \( 2448 + 8879 = 11327 \)

Answer:

11327