Question

a group of employees of unique services is to be surveyed with respect to a new pension plan. in - depth interviews are to be conducted with each employee selected in the sample. the employees are classified as follows.

classification	event	number of employees
maintenance	b	50
production	c	1,460
management	d	302
secretarial	e	68

what is the probability that the first person selected is classified as a maintenance employee?
○ a. 1.00
○ b. 0.025
○ c. 0.20
○ d. 0.50

Explanation:

Step1: Calculate total number of employees

$120 + 50 + 1460 + 302 + 68 = 2000$

Step2: Find probability of maintenance employee

$\text{Probability} = \frac{\text{Number of Maintenance Employees}}{\text{Total Employees}} = \frac{50}{2000} = 0.025$

Answer:

b. 0.025