Question

1. half a block from the corner store, jordan gives their skateboard one heroic kick, applying 9.6 n of forward force. unfortunately, the road has 2.1 n of friction working backward, and the headwind contributes another 0.7 n of resistance. gravity keeps them on the ground, so ignore the vertical direction. find the horizontal net force and direction.

Explanation:

Step1: Define forward force as positive

Let the forward - applied force $F_{applied}=9.6\ N$.

Step2: Define backward forces as negative

The friction force $F_{friction}=- 2.1\ N$ and the head - wind resistance $F_{wind}=-0.7\ N$.

Step3: Calculate the net force

The net force $F_{net}$ in the horizontal direction is given by the sum of all horizontal forces. So, $F_{net}=F_{applied}+F_{friction}+F_{wind}$.
Substitute the values: $F_{net}=9.6+( - 2.1)+( - 0.7)$.
First, add the negative forces: $2.1 + 0.7=2.8$. Then, $F_{net}=9.6-2.8$.
$F_{net}=6.8\ N$.
Since $F_{net}>0$, the direction is forward.

Answer:

The horizontal net force is $6.8\ N$ and the direction is forward.