Question

here is a data set. 33, 44, 32, 44, 47, 37, 44, 33, 44, 34. find the mean, median, mode, range, and standard deviation of the new data set obtained after multiplying each value by 0.6 in the data set above. round your answer for the standard deviation to the nearest thousandth. mean of the new data set: median of the new data set: mode of the new data set: range of the new data set: standard deviation of the new data set:

Explanation:

Step1: Multiply each data - point

The original data set is \(33,44,32,44,47,37,44,33,44,34\). Multiply each value by \(0.6\) to get the new data set: \(33\times0.6 = 19.8\), \(44\times0.6=26.4\), \(32\times0.6 = 19.2\), \(44\times0.6 = 26.4\), \(47\times0.6=28.2\), \(37\times0.6 = 22.2\), \(44\times0.6=26.4\), \(33\times0.6 = 19.8\), \(44\times0.6=26.4\), \(34\times0.6 = 20.4\). The new data set is \(19.8,26.4,19.2,26.4,28.2,22.2,26.4,19.8,26.4,20.4\).

Step2: Calculate the mean

The mean \(\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}\), where \(n = 10\) and \(\sum_{i=1}^{10}x_{i}=19.8 + 26.4+19.2+26.4+28.2+22.2+26.4+19.8+26.4+20.4=231\). So, \(\bar{x}=\frac{231}{10}=23.1\).

Step3: Calculate the median

First, order the data set: \(19.2,19.8,19.8,20.4,22.2,26.4,26.4,26.4,26.4,28.2\). Since \(n = 10\) (even), the median is the average of the \(\frac{n}{2}\) - th and \((\frac{n}{2}+1)\) - th ordered values. \(\frac{n}{2}=5\) and \(\frac{n}{2}+1 = 6\). The median is \(\frac{22.2 + 26.4}{2}=24.3\).

Step4: Calculate the mode

The mode is the most frequently - occurring value. In the new data set, \(26.4\) appears \(4\) times, so the mode is \(26.4\).

Step5: Calculate the range

The range is the difference between the maximum and minimum values. The maximum value is \(28.2\) and the minimum value is \(19.2\). So the range is \(28.2-19.2 = 9\).

Step6: Calculate the standard deviation

The formula for the sample standard deviation \(s=\sqrt{\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}}\).
\((19.2-23.1)^{2}=(-3.9)^{2}=15.21\), \((19.8 - 23.1)^{2}=(-3.3)^{2}=10.89\), \((19.8-23.1)^{2}=(-3.3)^{2}=10.89\), \((20.4-23.1)^{2}=(-2.7)^{2}=7.29\), \((22.2-23.1)^{2}=(-0.9)^{2}=0.81\), \((26.4-23.1)^{2}=3.3^{2}=10.89\), \((26.4-23.1)^{2}=3.3^{2}=10.89\), \((26.4-23.1)^{2}=3.3^{2}=10.89\), \((26.4-23.1)^{2}=3.3^{2}=10.89\), \((28.2-23.1)^{2}=5.1^{2}=26.01\).
\(\sum_{i = 1}^{10}(x_{i}-23.1)^{2}=15.21+10.89+10.89+7.29+0.81+10.89+10.89+10.89+10.89+26.01 = 114.7\).
\(s=\sqrt{\frac{114.7}{9}}\approx3.563\).

Answer:

Mean of the new data set: \(23.1\)
Median of the new data set: \(24.3\)
Mode of the new data set: \(26.4\)
Range of the new data set: \(9\)
Standard deviation of the new data set: \(3.563\)