Question

here are the numbers in expanded form.
547 = 500 + 40 + 7
186 = 100 + 80 + 6
subtract the hundreds, the tens, and the ones. you will need to regro
547 - 186 = \square + \square + \square
now find the answer.
547 - 186 = \square

Explanation:

Step1: Subtract hundreds place

Hundreds digit of 547 is 5 (representing 500), hundreds digit of 186 is 1 (representing 100). So \(500 - 100 = 400\)? Wait, no, wait. Wait, actually, when subtracting 547 - 186, we need to check if we need to regroup. Wait, 547 in expanded form is 500 + 40 + 7, 186 is 100 + 80 + 6. But when subtracting tens place: 40 - 80, we can't do that, so we need to regroup. So we borrow 1 from the hundreds place. So 500 becomes 400, and 40 becomes 140. Now:

Hundreds: \(500 - 100\) but after regrouping, it's \(400\) (wait, no, original hundreds: 500, but we borrow 1 (which is 100) to the tens place, so hundreds becomes \(500 - 100 = 400\)? Wait, no, let's do it properly. Let's expand with regrouping.

Wait, 547 - 186. Let's do place by place with regrouping:

• Ones place: 7 - 6 = 1
• Tens place: 4 - 8. Can't do, so we borrow 1 from hundreds. So hundreds: 5 becomes 4 (so 500 becomes 400), and tens: 4 becomes 14 (so 40 becomes 140). Now tens: 140 - 80 = 60
• Hundreds place: 400 - 100 = 300

Wait, wait, maybe I messed up earlier. Let's re-express 547 after regrouping for tens:

547 = (500 - 100) + (40 + 100) + 7 = 400 + 140 + 7. Now subtract 186 = 100 + 80 + 6.

So:

• Hundreds: 400 - 100 = 300
• Tens: 140 - 80 = 60
• Ones: 7 - 6 = 1

So now, 547 - 186 = (400 - 100) + (140 - 80) + (7 - 6) = 300 + 60 + 1.

Then, adding those: 300 + 60 + 1 = 361.

Wait, let's check: 300 + 60 = 360, 360 + 1 = 361. And 186 + 361 = 547. Yes, that works.

Wait, so earlier mistake: when we borrow 1 from hundreds (which is 100) to tens, so hundreds becomes 500 - 100 = 400? No, wait, 5 in hundreds place is 500. If we borrow 1 (which is 100) to the tens place, then hundreds becomes 500 - 100 = 400, and tens becomes 40 + 100 = 140. So that's correct.

So step by step:

Step1: Subtract hundreds (after regrouping)

After regrouping, 547's hundreds part (after borrowing for tens) is 400, 186's hundreds is 100. So \(400 - 100 = 300\)

Step2: Subtract tens (after regrouping)

After regrouping, 547's tens part is 140 (since we borrowed 100 from hundreds to tens: 40 + 100 = 140), 186's tens is 80. So \(140 - 80 = 60\)

Step3: Subtract ones

547's ones is 7, 186's ones is 6. So \(7 - 6 = 1\)

So \(547 - 186 = 300 + 60 + 1\)

Then, adding those: 300 + 60 + 1 = 361.

Wait, let's verify: 186 + 361 = 547. 186 + 300 = 486, 486 + 60 = 546, 546 + 1 = 547. Correct.

So first, the expanded subtraction with regrouping: 547 - 186 = (400 - 100) + (140 - 80) + (7 - 6) = 300 + 60 + 1. Then the total is 300 + 60 + 1 = 361.

Answer:

First, \(547 - 186 = \boldsymbol{300} + \boldsymbol{60} + \boldsymbol{1}\)

Then, \(547 - 186 = \boldsymbol{361}\)