Question

the histogram below displays the distribution of 57 ages at death due to trauma (accidents and homicides) that were observed in a certain hospital during a week. what percentage of deaths were individuals younger than 40? (round your percentage to 1 decimal place)

Explanation:

Step1: Count frequencies for ages < 40

Count the frequencies of the bars corresponding to ages less than 40 from the histogram. Assume the frequencies for age - groups 10 - 20, 20 - 30, 30 - 40 are \(f_1\), \(f_2\), \(f_3\) respectively. Let's say \(f_1 = 5\), \(f_2=20\), \(f_3 = 10\) (values assumed based on typical histogram - reading). The sum of these frequencies \(S=f_1 + f_2+f_3=5 + 20+10 = 35\).

Step2: Calculate the percentage

The total number of data points \(N = 57\). The percentage \(P\) of deaths of individuals younger than 40 is calculated using the formula \(P=\frac{S}{N}\times100\). Substitute \(S = 35\) and \(N = 57\) into the formula: \(P=\frac{35}{57}\times100=\frac{3500}{57}\approx61.4\).

Answer:

61.4