Question

homework 5 begin date: 8/17/2025 11:00:00 pm due date: 9/30/2025 11:59:00 pm end date: 9/30/2025 11:59:00 pm problem 10: (8% of assignment value) riders in an amusement park ride shaped like a viking ship hung from a large pivot are rotated back and forth like a rigid pendulum. at each end of the swing the ship hangs motionless for a moment before the ship swings down under the influence of gravity. assume that this motionless point occurs when the bar connecting the pivot point and the ship is horizontal. randomized variables r = 16 m m = 55 kg part (a) assuming negligible friction, find the speed of the riders at the bottom of its arc, given the systems center of mass travels in an arc having a radius of 16 m and the riders are near the center of mass in m/s. v = 17.70 correct! part (b) what is the centripetal acceleration at the bottom of the arc in m/s^2? a_c = blank grade summary deductions 0% potential 100% submissions attempts remaining: 3 (4% deduction per attempt) detailed view

Explanation:

Step1: Recall centripetal - acceleration formula

The formula for centripetal acceleration is $a_c=\frac{v^{2}}{r}$, where $v$ is the speed and $r$ is the radius of the circular path.

Step2: Substitute given values

We are given that $v = 17.70\ m/s$ and $r=16\ m$. Substitute these values into the formula: $a_c=\frac{(17.70)^{2}}{16}$.

Step3: Calculate the result

First, calculate $(17.70)^{2}=313.29$. Then, $\frac{313.29}{16}=19.580625\ m/s^{2}$.

Answer:

$19.58\ m/s^{2}$