QUESTION IMAGE
Question
homework helper
stephen’s father gave him $10 to buy lunch at the concession stand. if his lunch cost $7.74, how much change should stephen give his father?
find $10 - $7.74.
estimate 10 - 8 = 2
1 line up the decimal points. annex zeros so that both numbers end in the same place value.
2 subtract the digits in the same place - value positions. rename as necessary.
3 bring the decimal point straight down in the difference.
so, stephen should give his father $2.26.
check use addition to check your answer.
$2.26 + $7.74 = $10.00
practice
subtract. use addition to check your answer.
1.
\
- 71.65 - 55.12 =
3.
\
Problem 1: \(
\)
Step 1: Line up decimals
Ensure decimal points are aligned:
Step 2: Subtract hundredths place
\( 3 - 9 \) is not possible, so borrow from tenths place. Tenths place: \( 0 \) becomes \( -1 \), so we borrow from ones place. Ones place: \( 9 \) becomes \( 8 \), tenths place becomes \( 10 \), then borrow \( 1 \) from tenths to hundredths: tenths becomes \( 9 \), hundredths becomes \( 13 \). Now subtract hundredths: \( 13 - 9 = 4 \).
Step 3: Subtract tenths place
Tenths place: \( 9 - 0 = 9 \) (wait, no: original tenths after borrowing: we had \( 10 \) tenths, gave \( 1 \) to hundredths, so \( 9 \) tenths. Subtract \( 0 \) (from \( 4.09 \) tenths): \( 9 - 0 = 9 \)? Wait, no, let's redo. Wait, \( 9.03 \) is \( 9 + 0.03 \), \( 4.09 \) is \( 4 + 0.09 \). Wait, correct borrowing:
Ones: \( 9 \), tenths: \( 0 \), hundredths: \( 3 \)
Subtract \( 4.09 \): ones \( 4 \), tenths \( 0 \), hundredths \( 9 \)
Hundredths: \( 3 < 9 \), so we need to borrow from tenths. But tenths is \( 0 \), so we borrow from ones: ones becomes \( 8 \), tenths becomes \( 10 \) tenths. Now, borrow \( 1 \) tenth (which is \( 10 \) hundredths) to hundredths: tenths becomes \( 9 \) tenths, hundredths becomes \( 13 \) hundredths.
Now subtract hundredths: \( 13 - 9 = 4 \)
Subtract tenths: \( 9 - 0 = 9 \) (wait, no, the other number's tenths is \( 0 \), so \( 9 - 0 = 9 \))
Subtract ones: \( 8 - 4 = 4 \)
Wait, no, let's do it properly:
Wait, no, \( 9.03 - 4.09 \):
\( 9.03 - 4.09 = (9 - 4) + (0.03 - 0.09) = 5 + (-0.06) = 4.94 \). Wait, my borrowing was wrong earlier. Let's use decimal subtraction:
\( 9.03 - 4.09 = (8 + 1.03) - 4.09 = 8 - 4 + (1.03 - 4.09) \)? No, better to write as \( 9.03 = 8.9 + 0.13 \), \( 4.09 = 4.0 + 0.09 \). Then \( 8.9 - 4.0 = 4.9 \), \( 0.13 - 0.09 = 0.04 \), so total \( 4.9 + 0.04 = 4.94 \).
Step 4: Check with addition
\( 4.94 + 4.09 = 9.03 \), which matches the minuend. So the result is \( 4.94 \).
Step 1: Line up decimals
Step 2: Subtract hundredths place
\( 5 - 2 = 3 \)
Step 3: Subtract tenths place
\( 6 - 1 = 5 \)
Step 4: Subtract ones place
\( 1 - 5 \) is not possible, so borrow from tens place. Tens place: \( 7 \) becomes \( 6 \), ones place becomes \( 11 \). Now subtract ones: \( 11 - 5 = 6 \)
Step 5: Subtract tens place
\( 6 - 5 = 1 \)
Step 6: Combine results
Tens: \( 1 \), ones: \( 6 \), tenths: \( 5 \), hundredths: \( 3 \), so \( 16.53 \)
Step 7: Check with addition
\( 16.53 + 55.12 = 71.65 \), which matches.
Step 1: Line up decimals
Step 2: Subtract hundredths place
\( 4 - 5 \) is not possible, so borrow from tenths place. Tenths place: \( 9 \) becomes \( 8 \), hundredths becomes \( 14 \). Subtract hundredths: \( 14 - 5 = 9 \)
Step 3: Subtract tenths place
\( 8 - 2 = 6 \)
Step 4: Subtract ones place
\( 8 - 3 = 5 \) (wait, ones place of \( 18.94 \) is \( 8 \), subtract \( 3 \) from \( 3.25 \) ones: \( 8 - 3 = 5 \))
Step 5: Subtract tens place
\( 1 - 0 = 1 \) (tens place of \( 3.25 \) is \( 0 \))
Step 6: Combine results
Tens: \( 1 \), ones: \( 5 \), tenths: \( 6 \), hundredths: \( 9 \), so \( \$15.69 \)
Step 7: Check with addition
\( \$15.69 + \$3.25 = \$18.94 \), which matches.
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\( 4.94 \)