Question

homework: module a part 1 review
score: 18/30 answered: 18/30
question 19
use the order of operations to simplify this expression
$\left(\frac{2}{3}+\frac{1}{6}\
ight)\cdot\frac{2}{3}$

Explanation:

Step1: Calculate sum in parentheses

Find a common - denominator for $\frac{2}{3}$ and $\frac{1}{6}$. The common denominator is 6. So $\frac{2}{3}+\frac{1}{6}=\frac{2\times2}{3\times2}+\frac{1}{6}=\frac{4}{6}+\frac{1}{6}=\frac{4 + 1}{6}=\frac{5}{6}$.

Step2: Multiply the result by $\frac{2}{3}$

$\frac{5}{6}\times\frac{2}{3}=\frac{5\times2}{6\times3}=\frac{10}{18}=\frac{5}{9}$.

Answer:

$\frac{5}{9}$