Question

1. in horses, coat color black (b) is dominant over chestnut (b). the trotting gait is dominant (t) over the pacing gait (t). if a homozygous black pacer is mated to a homozygous chestnut, heterozygous trotter, what will be the genotypes and phenotypes of the offspring? show your work in the form of a punnett square and write your answers as a phenotypic ratio.7. tall sunflowers are dominant to short, while yellow-colored flowers are dominant to orange. cross a plant that is heterozygous for both traits with a plant that is heterozygous for height, but homozygous dominant for flower color. what will be the possible genotypes and phenotypes of the offspring? show your work as a punnett square and write your answers as a phenotypic ratio.

Explanation:

For Question 6:

Step1: Identify parent genotypes

Homozygous black pacer: $BBtt$; Homozygous chestnut heterozygous trotter: $bbTt$

Step2: List gametes for each parent

Gametes from $BBtt$: $Bt$ (all identical)
Gametes from $bbTt$: $bT$, $bt$ (1:1 ratio)

Step3: Build Punnett Square

	$Bt$	$Bt$
$bt$	$Bbtt$	$Bbtt$

Step4: Determine genotypes/phenotypes

• $BbTt$: Black coat, trotting gait
• $Bbtt$: Black coat, pacing gait

Step5: Calculate phenotypic ratio

2 out of 4 offspring are black trotters, 2 out of 4 are black pacers, simplified to 1:1.

Step1: Identify parent genotypes

Heterozygous for both traits: $TtYy$; Heterozygous height, homozygous dominant flower color: $TtYY$

Step2: List gametes for each parent

Gametes from $TtYy$: $TY$, $Ty$, $tY$, $ty$ (1:1:1:1 ratio)
Gametes from $TtYY$: $TY$, $tY$ (1:1 ratio)

Step3: Build Punnett Square

	$TY$	$Ty$	$tY$	$ty$
$tY$	$TtYY$	$TtYy$	$ttYY$	$ttYy$

Step4: Determine genotypes/phenotypes

• $TTYY$, $TTYy$, $TtYY$, $TtYy$: Tall, yellow flowers
• $ttYY$, $ttYy$: Short, yellow flowers

Step5: Calculate phenotypic ratio

6 out of 8 offspring are tall yellow, 2 out of 8 are short yellow, simplified to 3:1.

Answer:

Genotypes: $BbTt$, $Bbtt$
Phenotypic ratio: 1 Black trotter : 1 Black pacer

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For Question 7: