Question

c. how does the car’s kinetic energy at the bottom of the hill compare to its potential energy at the top?

Explanation:

In an ideal scenario (no friction, air resistance, etc.), mechanical energy is conserved. At the top of the hill, the car has gravitational potential energy (stored energy due to height) and minimal kinetic energy (since it's likely at rest or slow - moving). As it moves down the hill, potential energy is converted to kinetic energy. At the bottom, if we assume no energy losses, the kinetic energy should equal the potential energy at the top. In real - world situations with energy losses (like due to friction), the kinetic energy at the bottom would be less than the potential energy at the top, but typically in basic physics problems (conservation of energy context), we consider the ideal case where they are equal.

Answer:

In an ideal (no energy loss) situation, the car's kinetic energy at the bottom of the hill is equal to its potential energy at the top (due to conservation of mechanical energy). In real - world with energy losses (e.g., friction), the kinetic energy at the bottom is less than the potential energy at the top. (If considering ideal conservation, the answer is they are equal; if considering real - world, kinetic energy at bottom is less than potential energy at top.)