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Question
- how many feet of chrome edging are needed to finish a rectangular kitchen table? solve for: perimeter area volume surface area
- a public school wants to install rubber padding over a rectangular playground space that measures 22 feet by 15 feet. the padding comes in square tiles that measure 1 foot by 1 foot. how many tiles are needed? solve for: perimeter area volume surface area
- to prevent leakage, an oil storage tank is coated with sealant. how many square meters will need to be coated to cover the container? solve for: perimeter area volume surface area
- marisol wants to put a thin border on a quilt she made. the drawing shows the dimensions of the quilt. how many inches long is the border? solve for: perimeter area volume surface area
- how many cubic feet of water will the circular wading pool hold? solve for: perimeter area volume surface area
1. For the problem about the rectangular kitchen - table (finding how many feet of chrome edging are needed):
Step1: Identify the formula
The length of the edging around a rectangle is its perimeter. The formula for the perimeter of a rectangle is $P = 2(l + w)$, where $l$ is the length and $w$ is the width.
Step2: Substitute the values
If the length $l = 4$ ft and the width $w = 2$ ft, then $P=2(4 + 2)$.
Step3: Calculate
$P = 2\times6=12$ ft.
Step1: Identify the concept
We need to find the area of the rectangular playground to know how many 1 - foot by 1 - foot tiles are needed. The area formula for a rectangle is $A=l\times w$.
Step2: Substitute the values
Given $l = 22$ feet and $w = 15$ feet, then $A = 22\times15$.
Step3: Calculate
$A=330$ square feet. Since each tile has an area of 1 square foot, 330 tiles are needed.
Step1: Identify the shape and formula
The oil - storage tank is a cylinder. We need to find the surface area of the top, bottom, and the lateral surface. The surface area formula for a cylinder is $SA = 2\pi r^{2}+2\pi rh$, where $r$ is the radius and $h$ is the height. Given $r = 10$ m and $h = 25$ m.
Step2: Calculate the two parts
The area of the two circular bases is $2\pi r^{2}=2\pi(10)^{2}=200\pi$ square meters. The lateral surface area is $2\pi rh=2\pi\times10\times25 = 500\pi$ square meters.
Step3: Find the total surface area
$SA=200\pi + 500\pi=700\pi\approx700\times3.14 = 2198$ square meters.
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