Question

how many real - number solutions does the equation have? -2x² -5x = 0

Explanation:

Step1: Identify quadratic form

The equation is $-2x^2 -5x=0$, a quadratic equation.

Step2: Calculate discriminant

For $ax^2+bx+c=0$, discriminant $\Delta=b^2-4ac$. Here $a=-2$, $b=-5$, $c=0$.
$\Delta=(-5)^2-4(-2)(0)=25$

Step3: Analyze discriminant

Since $\Delta=25>0$, there are 2 real solutions.

Answer:

2