Question

how many solutions does the system of equations have? subtract 3x from both sides of the equation and rewrite the remaining values. \\(\

$$\begin{cases} y = 3x - 5 \\\\ y = -5 + 3x \\end{cases}$$

\\) \\(\

$$\begin{align} 3x - 5 &= -5 + 3x \\\\ \\underline{ - 3x \\quad \\quad \\quad \\quad \\quad \\quad - 3x} \\\\ \\square &= \\square \\end{align}$$

\\)

Explanation:

Step1: Subtract 3x from left side

For the left side \(3x - 5 - 3x\), the \(3x\) and \(-3x\) cancel out, leaving \(-5\).

Step2: Subtract 3x from right side

For the right side \(-5 + 3x - 3x\), the \(3x\) and \(-3x\) cancel out, leaving \(-5\).

Answer:

\(-5\)；\(-5\)