Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

1. how do the movements of sodium and potassium change during the actio…

Question

  1. how do the movements of sodium and potassium change during the action potential compared to during the resting membrane potential phase?
  1. after you stimulate the neuron, why do you have to wait before stimulating it again?
  1. what are the concentrations (in mm) of sodium (na⁺) ions inside and outside the cell at the end of the action potential, just before the ion levels start to return to normal? also, what are the concentrations of potassium (k⁺) ions inside and outside the cell at this same point?
  1. do the ion - concentration differences between resting potential and the end of an action potential surprise you? why or why not?
  1. which type of gated channel remains open longer? to determine this, use the sliding tool on the membrane potential vs. time chart and note when each gated channel opens and closes. pay special attention to the sodium gated channel, as it has a mechanism for locking that is different from potassiums.
  1. considering what youve learned in this simulation, explain why a potassium and/or sodium deficiency could lead to fatigue, confusion, muscle weakness, seizures, or stroke.

Explanation:

Response
Question 1
Brief Explanations

During resting membrane potential, the cell is at rest. The sodium - potassium pump maintains a high concentration of $K^+$ inside the cell and a high concentration of $Na^+$ outside the cell. The voltage - gated $Na^+$ and $K^+$ channels are closed (except for some leak channels, with $K^+$ leak channels being more permeable). So, there is very little net movement of $Na^+$ and $K^+$ across the membrane.

During the action potential:

  • Depolarization phase: When a stimulus reaches the threshold, voltage - gated $Na^+$ channels open rapidly. $Na^+$ ions, which are more concentrated outside the cell, rush into the cell down their electrochemical gradient. This causes the membrane potential to become more positive (depolarize).
  • Repolarization phase: After a short time (a few milliseconds), the voltage - gated $Na^+$ channels inactivate (a different state from closing). At the same time, voltage - gated $K^+$ channels open. $K^+$ ions, which are more concentrated inside the cell, flow out of the cell down their electrochemical gradient. This makes the membrane potential become more negative (repolarize) and move back towards the resting membrane potential.

In summary, during resting potential, there is minimal net movement of $Na^+$ and $K^+$ (mostly through leak channels). During action potential, $Na^+$ rapidly enters the cell (depolarization) and then $K^+$ rapidly exits the cell (repolarization).

Brief Explanations

After stimulating a neuron, we have to wait because of the refractory periods. There are two types of refractory periods:

  • Absolute refractory period: During this period, which corresponds to the time when voltage - gated $Na^+$ channels are inactivated (not just closed), the neuron cannot generate another action potential, no matter how strong the stimulus is. This is because the $Na^+$ channels need time to reset from the inactivated state to the closed state.
  • Relative refractory period: After the absolute refractory period, the voltage - gated $Na^+$ channels have reset to the closed state, but the voltage - gated $K^+$ channels are still open (or slowly closing). The membrane potential is more negative than the resting membrane potential (hyperpolarization). A stronger - than - normal stimulus can generate an action potential during this period, but we still need to wait for the neuron to return to its resting state (so that the ion concentrations and channel states are back to normal) to be able to stimulate it with a normal stimulus and get a reliable action potential.

These refractory periods ensure that action potentials are propagated in one direction and that the neuron has time to recover and be ready for the next potential stimulus.

Brief Explanations

At the end of the action potential (just before ion levels start to return to normal, which is before the activity of the sodium - potassium pump restores the ion concentrations), the concentrations are as follows:

  • Sodium ions ($Na^+$):
  • Inside the cell: The concentration of $Na^+$ inside the cell has increased from the resting state (which is typically around 10 mM) to a higher value, usually around 15 - 20 mM (this is a rough estimate, as the actual increase is relatively small compared to the large concentration gradient, but there is a net influx of $Na^+$ during depolarization).
  • Outside the cell: The concentration of $Na^+$ outside the cell has decreased slightly from the resting state (which is typically around 140 mM) to around 135 - 138 mM (due to the influx of $Na^+$ into the cell during depolarization).
  • Potassium ions ($K^+$):
  • Inside the cell: The concentration of $K^+$ inside the cell has decreased from the resting state (which is typically around 140 mM) to around 135 - 138 mM (due to the efflux of $K^+$ during repolarization).
  • Outside the cell: The concentration of $K^+$ outside the cell has increased from the resting state (which is typically around 5 mM) to around 8 - 10 mM (due to the efflux of $K^+$ from the cell during repolarization).

It should be noted that these are approximate values, and the actual values can vary slightly depending on the type of neuron and the experimental conditions. The sodium - potassium pump (which uses ATP to pump 3 $Na^+$ out and 2 $K^+$ in) will then start to operate to restore the resting ion concentrations.

Answer:

During resting membrane potential, there is minimal net movement of $Na^+$ (little influx) and $K^+$ (little efflux) across the membrane (due to the sodium - potassium pump and leak channels). During action potential, $Na^+$ rapidly enters the cell (depolarization phase) and $K^+$ rapidly exits the cell (repolarization phase) through voltage - gated channels.

Question 2