Question

how do the perimeters compare? original 30 in 36 in p = 132 in scaled 5 in 6 in p = 22 in the scaled rectangles perimeter is 1/6 the length of the original rectangles perimeter. the scaled rectangles perimeter is 1/8 the length of the original rectangles perimeter.

Explanation:

Step1: Identify the perimeters

Original perimeter $P_1 = 132$ in, scaled - perimeter $P_2=22$ in.

Step2: Calculate the ratio

Find the ratio $\frac{P_2}{P_1}=\frac{22}{132}=\frac{1}{6}$.

Answer:

The scaled rectangle's perimeter is $\frac{1}{6}$ the length of the original rectangle's perimeter.