Question

how would you expect the nuclide 7/3n to decay to result in a more stable nuclide? alpha decay beta decay of a positron beta decay of an electron gamma decay

Explanation:

The nuclide $\frac{7}{3}N$ has 3 protons and 4 neutrons. For light - weight nuclei, stable nuclei have a neutron - to - proton ratio close to 1. Here, the proton number is relatively low compared to the neutron number. Positron emission (beta decay of a positron) occurs when a proton is converted into a neutron, a positron, and a neutrino. This will increase the neutron - to - proton ratio and lead to a more stable nuclide. Alpha decay reduces the mass number and atomic number by 4 and 2 respectively and is not suitable for making this nuclide more stable. Beta decay of an electron increases the number of protons which is not needed here. Gamma decay only changes the energy state of the nucleus without changing the number of protons or neutrons.

Answer:

beta decay of a positron