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Question
how can you verify the converse of the pythagorean theorem using geogebra? a. by measuring angles directly b. by arranging squares visually c. by tracing geometric shapes d. by calculating numerical values what type of triangle is formed if the sides are a = 9, b = 12, and c = 15? a. right triangle b. acute triangle c. scalene triangle d. obtuse triangle
Step1: Recall Pythagorean theorem converse verification
The converse of the Pythagorean theorem is verified by checking if \(a^{2}+b^{2}=c^{2}\) for the side - lengths of a triangle. In GeoGebra, this is done by calculating numerical values of the squares of the side - lengths. Measuring angles directly (a) is not how the converse is verified. Arranging squares visually (b) is an intuitive way to understand the theorem itself but not the best way to verify the converse in GeoGebra. Tracing geometric shapes (c) has no relation to verifying the converse.
Step2: Determine triangle type using Pythagorean theorem
For a triangle with side - lengths \(a = 9\), \(b = 12\), and \(c = 15\), calculate \(a^{2}+b^{2}\) and \(c^{2}\).
\(a^{2}=9^{2}=81\), \(b^{2}=12^{2}=144\), so \(a^{2}+b^{2}=81 + 144=225\). And \(c^{2}=15^{2}=225\). Since \(a^{2}+b^{2}=c^{2}\), by the converse of the Pythagorean theorem, it is a right - triangle. An acute triangle has \(a^{2}+b^{2}>c^{2}\) for the longest side \(c\), an obtuse triangle has \(a^{2}+b^{2}
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- d. By calculating numerical values
- a. Right triangle