Question

Question was provided via image upload.

Explanation:

Step1: Box method: Find first term

To get $2x^2$ with $x$, multiply by $2x$.
Top right box: $2x \times (-7) = -14x$

Step2: Box method: Find second term

We need $-4x - (-14x) = 10x$ in the lower left.
$\frac{10x}{x} = 10$, so lower right: $10 \times (-7) = -70$

Step3: Long division: First term

Divide $2x^2$ by $x$: $2x$.
Multiply $(x-7)$ by $2x$: $2x^2 -14x$
Subtract: $(2x^2-4x)-(2x^2-14x)=10x$

Step4: Long division: Second term

Divide $10x$ by $x$: $10$.
Multiply $(x-7)$ by $10$: $10x-70$
Subtract: $(10x-70)-(10x-70)=0$

Answer:

$2x + 10$