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Question

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Explanation:

Step1: Factor numerators/denominators

$\frac{2y}{y-3} \cdot \frac{4(y-3)}{2(y+3)}$

Step2: Cancel common factors

Cancel $y-3$ and simplify $\frac{4}{2}=2$:
$\frac{2y}{1} \cdot \frac{2}{y+3}$

Step3: Multiply remaining terms

$\frac{2y \cdot 2}{y+3} = \frac{4y}{y+3}$

Answer:

$\boldsymbol{\frac{4y}{y+3}}$ (matches the option: $\boldsymbol{\frac{4y}{y+3}}$)