QUESTION IMAGE
Question
- in humans, the allele for tongue rolling (r) is dominant to the allele for non - tongue rolling (r). a man who is a non - roller marries and has offspring with a woman who is heterozygous.
a. what is the mother’s genotype? ____________
b. what is the father’s genotype? ____________
c. what is the chance of having a nonrolling child? ____________
d. what is the chance of having a rolling child? ____________
- in tomatoes, red fruit (r) is dominant to yellow fruit (r). cross a homozygous red tomato plant to a heterozygous plant.
a. what is the genotypic ratio? ____________
b. what is the phenotypic ratio? ____________
c. what is the chance of for red fruit? __________ yellow fruit? __________
- in cattle, the hornless condition (h) is dominant and the horned condition (h) is recessive. a bull without horns is crossed with a cow with horns. of the four offspring, 1 is horned and 3 are hornless.
a. what is the genotype of the bull? ____________
b. what is the genotype of the cow? ____________
c. what is the genotypic ratio? ____________
d. what is the phenotypic ratio? ____________
- in humans widow’s peak (h) is dominant over straight hairline (h). a man with a straight hairline has children with a women with two alleles for widow’s peak.
a. what is the chance that any offspring would have a widow’s peak? ____________
b. what is the chance that any offspring would not have a widow’s peak? ____________
c. genotypic ratio? ____________
matching vocabulary
______ 9. genotypes made from the same alleles
______ 10. different forms of genes for a single trait
______ 11. gene that is always expressed
______ 12. gene that is only expressed in the homozygous state
______ 13. genotype made of two different alleles.
a. alleles
b. dominant
c. heterozygous
d. homozygous
e. recessive
5.
Step1: Determine mother's genotype
The mother is heterozygous. So her genotype is Rr.
Step2: Determine father's genotype
The father is a non - roller. Since non - rolling is recessive, his genotype is rr.
Step3: Calculate probability of non - rolling child
The cross is Rr x rr. Using a Punnett - square, the possible genotypes are Rr and rr in a 1:1 ratio. The probability of having a non - rolling child (rr) is 50% or 1/2.
Step4: Calculate probability of rolling child
The probability of having a rolling child (Rr) is 50% or 1/2.
6.
Step1: Identify genotypes of parents
The homozygous red tomato plant has genotype RR and the heterozygous plant has genotype Rr.
Step2: Determine genotypic ratio
The cross is RR x Rr. The possible genotypes are RR and Rr in a 1:1 ratio. So the genotypic ratio is 1 RR : 1 Rr.
Step3: Determine phenotypic ratio
Since both RR and Rr result in red fruit, the phenotypic ratio is 100% red : 0% yellow or 1:0.
Step4: Calculate probabilities of fruit color
The chance of red fruit is 100% or 1, and the chance of yellow fruit is 0% or 0.
7.
Step1: Determine cow's genotype
The cow has horns, so its genotype is hh.
Step2: Determine bull's genotype
Since some offspring are horned (hh), the bull without horns must be heterozygous, so its genotype is Hh.
Step3: Calculate genotypic ratio
The cross is Hh x hh. The possible genotypes are Hh and hh in a 1:1 ratio. So the genotypic ratio is 1 Hh : 1 hh.
Step4: Calculate phenotypic ratio
The phenotypic ratio of hornless (Hh) to horned (hh) is 1:1.
8.
Step1: Identify parents' genotypes
The man with a straight hairline has genotype hh, and the woman with two alleles for widow's peak has genotype HH.
Step2: Calculate probability of widow's peak offspring
The cross is HH x hh. All offspring will have genotype Hh, so the chance of having a widow's peak offspring is 100% or 1.
Step3: Calculate probability of non - widow's peak offspring
The chance of having a non - widow's peak offspring is 0% or 0.
Step4: Determine genotypic ratio
The genotypic ratio is 1 Hh : 0 hh : 0 HH or simply 1 Hh.
Matching Vocabulary
- Genotypes made from the same alleles: D. homozygous
- Different forms of genes for a single trait: A. alleles
- Gene that is always expressed: B. dominant
- Gene that is only expressed in the homozygous state: E. recessive
- Genotype made of two different alleles: C. heterozygous
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5.
A. Rr
B. rr
C. 50% or 1/2
D. 50% or 1/2
6.
A. 1 RR : 1 Rr
B. 1 red : 0 yellow
C. 100% or 1, 0% or 0
7.
A. Hh
B. hh
C. 1 Hh : 1 hh
D. 1 hornless : 1 horned
8.
A. 100% or 1
B. 0% or 0
C. 1 Hh
- D. homozygous
- A. alleles
- B. dominant
- E. recessive
- C. heterozygous