Question

hw 2 - introduction to limits section 1.1: problem 2 (1 point)
as x gets closer and closer (but not equal) to 5, what value does $f(x)=\frac{x^{3}-125}{x^{2}-25}$ get closer and closer (but not equal) to?
fill out the table below to find out.

x	f(x)	x	f(x)
5.002	4.998
5.001	4.999
5.0005	4.9995
5.0001	4.999

as x gets closer and closer (but not equal) to 5, f(x) gets closer and closer to

Explanation:

Step1: Analyze the table data

As \(x\) values \(5.002,5.001,5.0005,5.0001\) get closer to \(5\), the corresponding \(f(x)\) values \(4.998,4.999,4.9995,4.9999\) are approaching a certain number.

Step2: Determine the limit value

The values of \(f(x)\) are approaching \(5\) as \(x\) approaches \(5\).

Answer:

\(5\)