Question

hw 2: problem 16
(1 point)
find the limit $lim_{y \to -\infty} \frac{8}{y - 2}$
enter 1 for $\infty$, -1 for $-\infty$, and dne if the limit does not exist.
answer:

Explanation:

Step1: Analyze denominator behavior

As $y \to -\infty$, $y-2 \to -\infty$.

Step2: Evaluate the fraction

We calculate $\lim_{y \to -\infty} \frac{8}{y-2} = \frac{8}{-\infty}$

Step3: Simplify the expression

A non-zero constant divided by negative infinity equals 0.

Answer:

0