Question

the image shows the path of a ball thats thrown. at positions and , kinetic energy is maximum. at position , potential energy is maximum.

Explanation:

Step1: Recall energy - height relationship

Kinetic energy ($KE=\frac{1}{2}mv^{2}$) is maximum when the speed of the ball is maximum. The speed of a ball thrown upwards is maximum at the lowest - height positions. Potential energy ($PE = mgh$) is maximum when the height ($h$) is maximum.

Step2: Identify maximum - KE positions

The ball has maximum kinetic energy at the lowest points of its path. In the given path of the ball, the lowest points are A and G.

Step3: Identify maximum - PE position

The ball has maximum potential energy at the highest point of its path. In the given path, the highest point is D.

Answer:

At positions A and G, kinetic energy is maximum. At position D, potential energy is maximum.