Question

instructions solve the following problem and choose the best answer. question during a 5 - day period, a florist served a different number of customers at a flower shop each day. the mean number of daily customers served during this period was 17. in the following month, during another 5 - day period, the florist served 16 customers per day for four of the days, but served 25 customers during each of the fifth day. what is the difference between the mean number of customers the florist served during the two five - day periods? adapted from khan academy. 0 0.8 1.0 2.4

Explanation:

Step1: Find total customers in first 5 - day period

Let the number of customers on the fifth day of the first 5 - day period be $x$. The sum of customers in the first 5 - day period with known values 16, 17, 16, 17 and $x$ is $16 + 17+16 + 17+x=66 + x$. The mean of this 5 - day period is 17. Using the mean formula $\text{Mean}=\frac{\text{Sum of values}}{\text{Number of values}}$, we have $17=\frac{66 + x}{5}$. Cross - multiplying gives $17\times5=66 + x$, so $85=66 + x$, and $x = 85−66=19$.

Step2: Find total customers in second 5 - day period

In the second 5 - day period, the number of customers on four days is 25 each. Let the total number of customers in the second 5 - day period be $S_2$. Then $S_2=4\times25 + y$ (where $y$ is the number of customers on the fifth day). The mean of this 5 - day period is also 17. So $17=\frac{100 + y}{5}$. Cross - multiplying gives $17\times5=100 + y$, so $85=100 + y$, and $y=- 15$ (this is wrong, we should use the correct approach of just comparing the means). Since the mean of both 5 - day periods is 17, the difference between the means is $|17 - 17|=0$.

Answer:

0