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int t^{4} dt = square + c

Question

int t^{4} dt = square + c

Explanation:

Step1: Recall the power rule for integration

The power rule for integration states that $\int t^n dt = \frac{t^{n + 1}}{n + 1} + C$ (where $n
eq -1$).

Step2: Apply the power rule to $\int t^4 dt$

Here, $n = 4$. Substituting into the power rule formula, we get $\frac{t^{4 + 1}}{4 + 1} + C$.

Step3: Simplify the expression

Simplifying $\frac{t^{5}}{5} + C$.

Answer:

$\frac{t^5}{5}$