Question

interaction simulation 1 discussion answer the following in the discussion below (click reply). find similarities in your classmates work, comment, how did you find that... on the differences. - four points per question, 8 points for classmate comments how does changing the amount of charge on two objects affect: the electric fields around the charged objects? the strength of the forces acting between the two objects? hints: what happens when one particle is positive? what happens when both particles are positive? what happens when you change the magnitude of the charges? what happens when the particles have different magnitudes of charge? what happens when one particle is neutral? what happens when one particle is neutral? write a reply edit view insert format tools table

Explanation:

Step1: Recall electric - field formula

The electric - field strength due to a point charge $q$ at a distance $r$ is given by $E = k\frac{q}{r^{2}}$, where $k$ is Coulomb's constant. If the charge $q$ on an object increases, the electric - field strength $E$ around it increases proportionally (assuming the distance $r$ from the charge remains the same). So, increasing the amount of charge on a charged object increases the magnitude of the electric field around it.

Step2: Recall Coulomb's law

Coulomb's law for the force $F$ between two point charges $q_1$ and $q_2$ separated by a distance $r$ is $F=k\frac{q_1q_2}{r^{2}}$. If we increase the magnitude of either $q_1$ or $q_2$ (or both), the force $F$ between the two charges increases. For example, if we double $q_1$, the force $F$ between the two charges doubles (assuming $q_2$ and $r$ remain constant).

Answer:

• Changing the amount of charge on two objects:
• Effect on electric fields: Increasing the charge on a charged object increases the magnitude of the electric field around it, as the electric - field strength $E$ is directly proportional to the charge $q$ ($E = k\frac{q}{r^{2}}$).
• Effect on the strength of forces between the two objects: Increasing the magnitude of the charge on either or both of the two objects increases the strength of the electrostatic force between them, according to Coulomb's law $F = k\frac{q_1q_2}{r^{2}}$.