Question

r is in the interior of ∠jkm. if m∠jkr = 150° and m∠jkm = 165°, what is the m∠rkm?

Explanation:

Step1: Recall angle - addition postulate

$\angle{JKM}=\angle{JKR}+\angle{RKM}$

Step2: Solve for $\angle{RKM}$

$\angle{RKM}=\angle{JKM}-\angle{JKR}$

Step3: Substitute given values

$\angle{RKM}=165^{\circ}- 150^{\circ}=15^{\circ}$

Answer:

$15^{\circ}$