Question

isoke is solving the quadratic equation by completing the square.
$10x^2 + 40x - 13 = 0$
$10x^2 + 40x = 13$
$a(x^2 + 4x) = 13$
what is the value of $a$?
options: 10, 40, -13, 4

Explanation:

Step1: Isolate variable terms

$10x^2 + 40x = 13$

Step2: Factor out coefficient of $x^2$

Compare $10(x^2 + 4x) = 13$ with $A(x^2 + 4x) = 13$

Answer:

10