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Question
an item is randomly drawn from a bag with 16 fruit cups, 3 vegetable cups, 14 fruit cans, and 7 vegetable cans. event a: fruit event b: can p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.
Step1: Calculate total number of items
$16 + 3+14 + 7=40$
Step2: Calculate P(A)
$P(A)=\frac{16 + 14}{40}=\frac{30}{40}=0.75$
Step3: Calculate P(B)
$P(B)=\frac{14 + 7}{40}=\frac{21}{40}=0.525$
Step4: Calculate P(A and B)
$P(A\text{ and }B)=\frac{14}{40}=0.35$
Step5: Calculate P(A or B)
$P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B)=0.75 + 0.525- 0.35=0.925\approx0.93$
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$0.93$