Question

my ixl learning assess
jj.6 calculate mean absolute deviation juv
learn with an example or wa
in the data set below, what is the mean absolute deviation?
7 6 8 5 3
if the answer is a decimal, round it to the nearest tenth.
mean absolute deviation (mad):
submit

Explanation:

Step1: Calculate the data mean

Find sum, divide by count:
$$\text{Mean} = \frac{7 + 6 + 8 + 5 + 3}{5} = \frac{29}{5} = 5.8$$

Step2: Find absolute deviations

Subtract mean from each value, take absolute value:
$|7 - 5.8| = 1.2$, $|6 - 5.8| = 0.2$, $|8 - 5.8| = 2.2$, $|5 - 5.8| = 0.8$, $|3 - 5.8| = 2.8$

Step3: Calculate MAD of deviations

Sum deviations, divide by count:
$$\text{MAD} = \frac{1.2 + 0.2 + 2.2 + 0.8 + 2.8}{5} = \frac{7.2}{5} = 1.44$$

Step4: Round to nearest tenth

Round 1.44 to one decimal place: $1.4$

Answer:

1.4