Question

keep going. lets try to get \\(\frac{2}{3}b\\) alone on the right side. how could you get rid of the 11 on the right side so that \\(\frac{2}{3}b\\) is alone on the right, while keeping the equation balanced? \\(\frac{2}{3}b + 9 = b + 11\\) \\(-\frac{2}{3}b\\) \\(-\frac{2}{3}b\\) \\(9 = \frac{1}{3}b + 11\\) options: divide both sides by 11, subtract 11 from both sides, add 11 to both sides

Explanation:

Step1: Identify target term

We need to isolate $\frac{1}{3}b$ on the right. The right side is $\frac{1}{3}b + 11$, so we eliminate 11.

Step2: Balance the equation

To remove +11, subtract 11 from both sides:
$$\frac{2}{3}b + 9 - 11 = \frac{1}{3}b + 11 - 11$$
Simplify both sides:
$$\frac{2}{3}b - 2 = \frac{1}{3}b$$

Answer:

Subtract 11 from both sides