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QUESTION IMAGE

a lab investigation will be conducted using potato (plant cells) and li…

Question

a lab investigation will be conducted using potato (plant cells) and liver (animal cells).

  1. draw and label the set up in the space provided.

also draw your observations of the bubbles.
underneath each drawing, record the measurement taken during the experiment.
table with columns: tube 1, tube 2, tube 3 (each with hand-drawn sketches and a measurement: row at the bottom)

  1. what is the purpose of this experiment?

handwritten text: the purpose of the experiment is to see how the catalase reacts with h₂o₂

  1. write a hypothesis for this experiment in \if…then…because…\ format.

partially visible handwritten text

Explanation:

Response
Question 2:
Brief Explanations

The experiment uses plant (potato) and animal (liver, blood) cells with \( \ce{H2O2} \) (implied by bubble observations, likely catalase activity). Purpose is to compare catalase activity (enzyme breaking down \( \ce{H2O2} \)) in plant vs animal cells, or test which tissue (potato, liver, blood) has more catalase (via bubble production, a sign of \( \ce{H2O2} \) decomposition).

Brief Explanations

Catalase is an enzyme in cells that breaks down \( \ce{H2O2} \). Animal cells (like liver, blood) or plant cells (potato) can be hypothesized to have more activity. Structure: "If [tissue] is used, then [more/less bubbles] will form, because [tissue type has higher/lower catalase concentration]." Example: If liver (or blood) is used, then more bubbles will form than with potato, because animal cells (liver/blood) have higher catalase activity to detoxify \( \ce{H2O2} \).

Answer:

The purpose of this experiment is to compare the catalase activity (ability to break down hydrogen peroxide, \( \ce{H2O2} \)) in plant cells (potato) and animal cells (liver, blood) by observing and measuring the rate/amount of bubble production (indicating \( \ce{H2O2} \) decomposition).

Question 3: