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QUESTION IMAGE

latasha was presented with the following data set and argued that there…

Question

latasha was presented with the following data set and argued that there was no correlation between x and y. is latasha correct? use the regression equation to explain your reasoning.

x1234567
y4545454

Explanation:

Step1: Calculate the means of \(x\) and \(y\)

The mean of \(x\) values \(\bar{x}=\frac{1 + 2+3+4+5+6+7}{7}=\frac{28}{7} = 4\).
The mean of \(y\) values \(\bar{y}=\frac{4 + 5+4+5+4+5+4}{7}=\frac{31}{7}\approx4.43\).

Step2: Calculate the slope \(b_1\) of the regression line

The formula for \(b_1=\frac{\sum_{i = 1}^{n}(x_i-\bar{x})(y_i - \bar{y})}{\sum_{i=1}^{n}(x_i-\bar{x})^2}\)
\(\sum_{i = 1}^{7}(x_i - 4)(y_i-4.43)\):
\((1 - 4)(4 - 4.43)+(2 - 4)(5 - 4.43)+(3 - 4)(4 - 4.43)+(4 - 4)(5 - 4.43)+(5 - 4)(4 - 4.43)+(6 - 4)(5 - 4.43)+(7 - 4)(4 - 4.43)\)
\(=(- 3)(-0.43)+(-2)(0.57)+(-1)(-0.43)+(0)(0.57)+(1)(-0.43)+(2)(0.57)+(3)(-0.43)\)
\(=1.29-1.14 + 0.43+0-0.43+1.14-1.29=0\)
\(\sum_{i=1}^{7}(x_i - 4)^2=(1 - 4)^2+(2 - 4)^2+(3 - 4)^2+(4 - 4)^2+(5 - 4)^2+(6 - 4)^2+(7 - 4)^2\)
\(=9 + 4+1+0+1+4+9 = 28\)
Since \(b_1=\frac{0}{28}=0\), the regression equation is \(y=b_0 + 0x=b_0\) (where \(b_0=\bar{y}\approx4.43\)).

Step3: Analyze the correlation

A slope of \(0\) in the regression equation indicates that there is no linear - relationship between \(x\) and \(y\).

Answer:

LaTasha is correct. There is no linear correlation between \(x\) and \(y\) as the slope of the regression line is \(0\).