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the length of a rectangle is twice its width. the area of the rectangle…

Question

the length of a rectangle is twice its width. the area of the rectangle is 32 square feet. what are the length and width? which equation models this problem? o 32w = 2w + w o w - 2w = 32 o 2w·w = 32 o 2w + w = 32

Explanation:

Step1: Recall rectangle - area formula

The area formula of a rectangle is $A = l\times w$, where $l$ is the length and $w$ is the width. Given that $l = 2w$ and $A=32$.

Step2: Substitute values into formula

Substitute $l = 2w$ and $A = 32$ into $A=l\times w$. We get $32=2w\times w$.

Answer:

The correct equation is $2w\cdot w = 32$.