Question

the length and width of a rectangle pqrs are $x^{2}-5x + 6$ and $x - 3$. what is the perimeter of rectangle pqrs?
$x^{2}-4x + 3$
$2x^{2}-8x + 6$
$2x^{2}-12x - 6$
$2x^{2}-12x + 6$

Explanation:

Step1: Recall perimeter formula

$P = 2(l + w)$ where $l=x^{2}-5x + 6$ and $w=x - 3$.

Step2: Substitute and simplify

$P=2((x^{2}-5x + 6)+(x - 3))=2(x^{2}-4x + 3)=2x^{2}-8x + 6$.

Answer:

$2x^{2}-8x + 6$