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Question
lesson 4: operations with radicals - (addition & subtraction)
do now: write each answer in simplest radical form;
- $-sqrt{2}(3sqrt{2})$
- $\frac{8sqrt{12}}{2sqrt{3}}$
steps for addition & subtraction:
- simplify all radicals
- combine the coefficients with identical numbers under the square root
example 1: $2sqrt{7} + 5sqrt{3} - 4sqrt{3}$
example 2: $6sqrt{50} - 2sqrt{8}$
practice:
- $7sqrt{2} + 6sqrt{2}$
- $12sqrt{5} - 8sqrt{5}$
- $3sqrt{3} + sqrt{12}$
- $sqrt{18} - sqrt{2}$
- $9sqrt{8} - sqrt{50}$
- $-sqrt{18} - sqrt{98}$
Step1: Simplify $\boldsymbol{-\sqrt{2}(3\sqrt{2})}$
Multiply coefficients and radicals:
$-\sqrt{2}(3\sqrt{2}) = -3 \times \sqrt{2 \times 2} = -3 \times 2 = -6$
Step2: Simplify $\boldsymbol{\frac{8\sqrt{12}}{2\sqrt{3}}}$
Simplify coefficients and radicals:
$\frac{8}{2} \times \frac{\sqrt{12}}{\sqrt{3}} = 4 \times \sqrt{\frac{12}{3}} = 4 \times \sqrt{4} = 4 \times 2 = 8$
Step3: Combine $\boldsymbol{7\sqrt{2} + 6\sqrt{2}}$
Add like radical coefficients:
$(7+6)\sqrt{2} = 13\sqrt{2}$
Step4: Combine $\boldsymbol{12\sqrt{5} - 8\sqrt{5}}$
Subtract like radical coefficients:
$(12-8)\sqrt{5} = 4\sqrt{5}$
Step5: Simplify $\boldsymbol{3\sqrt{3} + \sqrt{12}}$
Rewrite $\sqrt{12}$, then combine:
$3\sqrt{3} + \sqrt{4 \times 3} = 3\sqrt{3} + 2\sqrt{3} = (3+2)\sqrt{3} = 5\sqrt{3}$
Step6: Simplify $\boldsymbol{\sqrt{18} - \sqrt{2}}$
Rewrite $\sqrt{18}$, then combine:
$\sqrt{9 \times 2} - \sqrt{2} = 3\sqrt{2} - \sqrt{2} = (3-1)\sqrt{2} = 2\sqrt{2}$
Step7: Simplify $\boldsymbol{9\sqrt{8} - \sqrt{50}}$
Rewrite radicals, then combine:
$9\sqrt{4 \times 2} - \sqrt{25 \times 2} = 9 \times 2\sqrt{2} - 5\sqrt{2} = 18\sqrt{2} - 5\sqrt{2} = (18-5)\sqrt{2} = 13\sqrt{2}$
Step8: Simplify $\boldsymbol{-\sqrt{18} - \sqrt{98}}$
Rewrite radicals, then combine:
$-\sqrt{9 \times 2} - \sqrt{49 \times 2} = -3\sqrt{2} - 7\sqrt{2} = (-3-7)\sqrt{2} = -10\sqrt{2}$
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