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lesson 6 | session 4 2 a middle school has an oval track with the dimen…

Question

lesson 6 | session 4
2 a middle school has an oval track with the dimensions shown. what is the distance around the track? use 3.14 for π. show your work.
78 m
78 m

Explanation:

Step1: Identify the track - components

The oval track consists of two semi - circles (which form a full circle) and two straight sections.

Step2: Calculate the circumference of the circle

The diameter of the circle formed by the two semi - circles is \(d = 78\) m. The formula for the circumference of a circle is \(C=\pi d\). Using \(\pi = 3.14\) and \(d = 78\) m, we have \(C = 3.14\times78=244.92\) m.

Step3: Calculate the length of the two straight sections

The length of each straight section is 78 m, and the total length of the two straight sections is \(2\times78 = 156\) m.

Step4: Calculate the total distance around the track

The total distance \(D\) around the track is the sum of the circumference of the circle and the length of the two straight sections. So \(D=244.92 + 156=400.92\) m.

Answer:

400.92 m